Question 771610
let {{{ y }}} = the current year by year salary
Let {{{ x }}} = the 1st years salary
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What is wanted is:
{{{ y[0] + y[1] + y[2] }}}. . . up to {{{ y[23] }}}
which is the lifetime salary
The sequence looks like
{{{ x*( 1.08 )^0 + x*( 1.08)^1 + x*( 1.08 )^2 }}}. . .  {{{ x*( 1.08 )^23 }}}
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The formula for this sum is:
{{{ x*( 1 - 1.08^24 ) / ( 1 - 1.08 ) }}}
{{{ x = 30000 }}}
{{{ 30000*( 1 - 6.341181 ) / ( - .08 ) }}}
{{{ 30000*( -5.341181 / -.08 ) }}}
{{{ 30000*66.76476 }}}
{{{ 2002942.78 }}}
I got your answer.
The method seems right. 
???