Question 771456
with equation x – 5y = 25
5y=x-25
/5
y=(1/5)x -5
slope m1 = (1/5)

L2 with equation 5x + y = 5
y=-5x+5
slope m2=-5

m1 * m2 = (1/5)*(-5) =-1

therefore the lines are perpendicular