Question 771285
a train left a station at noon going 40 mph. a second train left at 3 p.m. going 60mph. at what time will the second train catch up to the first

The distance traveled by two trains will be same when they meet. Only the times are different

Let them meet after time t after the first train starts

distance traveled by first train =40t
time taken by second train = 60(t-3) ( it starts 3 hours late)

40t=60(t-3)

40t=60t-180

20t=180
t=9 

The second train will catch up at 9.00 pm