Question 771270
{{{LCM(x^2,2x-6,2x+4)=LCM(x^2,2(x-3),2(x+2))=highlight(2x^2(x-3)(x+2))}}}
Excluded solutions are the values of {{{x}}} trhat make one (or more) of the denominators equal to {{{0}}}. They are:
{{{x^2=0}}}-->{{{highlight(x=0)}}}
{{{2(x-3)=0}}}-->{{{highlight(x=3)}}} and
{{{2(x+2)=0}}}-->{{{highlight(x=-2)}}}