Question 770959
x for length and y for width, so area is xy and perimeter is 2x+2y.


{{{xy=80}}} and {{{2x+2y=42}}}
{{{x+y=21}}}
{{{y=21-x}}}
Substitute into area equation
{{{x(21-x)=80}}}
{{{21x-x^2=80}}}
{{{-x^2+21x-80=0}}}
{{{x^2-21x+80=0}}}
{{{(x-16)(x-5)=0}}}

One dimension is 5 meters and the other dimension is 16 meters.