Question 770925
Use the Pythagorean identity sin^2t+cos^2t=1 to show that cot^2t=csc^2t-1
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cot^2t=csc^2t-1
Start with right hand side:
{{{csc^2(t)-1}}}
{{{1/sin^2(t)-1}}}
{{{(sin^2(t)+cos^2(t))/sin^2(t)-1}}}
{{{1+cot^2(t)-1}}}
=cot^2(t)
Verified:
Right-hand side=left-hand side