Question 770853
{{{9x^3-3x^2-3x+1=0}}} rearrange terms

{{{9x^3-3x-3x^2+1 = 0}}}.....group

{{{(9x^3-3x)-(3x^2-1) = 0}}}....factor

{{{3x(3x^2-1)-(3x^2-1) = 0}}}

{{{(3x-1)(3x^2-1) = 0}}}


if {{{(3x-1) = 0}}} then {{{3x=1}}} => {{{x=1/3}}}

if {{{(3x^2-1) = 0}}} then {{{3x^2=1}}} => {{{x^2=1/3}}}=> {{{x=sqrt(1/3)}}}

=> {{{sqrt(1/3)=1/sqrt(3)}}}=>{{{sqrt(3)/3}}} or {{{-sqrt(3)/3}}}

solutions:

 {{{x=1/3}}}
{{{sqrt(3)/3}}} 
{{{-sqrt(3)/3}}}

{{{ graph( 600, 600, -5, 5, -5, 10, 9x^3-3x^2-3x+1) }}}