Question 770834
You have a circle and an ellipse.  Finding a solution by graphing is not any addition nor substitution method.  Graphing is put the graph onto a coordinate system.  Know how the equations work.  


Your circle is simply a unit circle at the origin.  The other equation is an ellipse.  Divide by sides by 49 so the standard form is more readable.

{{{(x^2)/7^2+y^2=1}}} which is also centered at the origin.  The intercepts on the y-axis are at plus and minus 1; the intercepts on the x-axis are at plus and minus 7.  Note that standard form centered at origin for an ellipse is like, 
{{{x^2/a^2+y^2/b^2=1}}} for when a>b, and the x intercepts are plus and minus a, and y-intercepts are at plus and minus b.  


Showing just the lower half of each graphed figure:

{{{graph(350,350,-10,10,-5,5,-sqrt(1-(x^2)/49),-sqrt(1-x^2))}}}


Showing just the upper half of each graphed figure:

{{{graph(350,350,-10,10,-5,5,sqrt(1-(x^2)/49),sqrt(1-x^2))}}}

They are displaying a bit imperfectly.