Question 770821
1. 
{{{xy=-220}}}
{{{x=-220/y}}} --> Equation 1 ... Substitute {{{x=-220/y}}} into Equation 2
{{{x+y=-12}}} --> Equation 2
{{{-220/y+y=-12}}}
{{{y*(-220/y)+y*(y)=y*(-12)}}}
{{{y^2+12y-220=0}}}
{{{(y+22)(y-10)=0}}}
{{{y=-22}}} or {{{y=10}}}
When {{{y=-22}}},
{{{x=-220/-22}}}={{{x=10}}}
When {{{y=10}}},
{{{x=-220/10}}}={{{x=-22}}}
Therefore, the two numbers are -22 and 10.
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2. (Use the same steps)
{{{xy=264}}}
{{{x=264/y}}} --> Equation 1 ... Substitute {{{x=264/y}}} into Equation 2
{{{x+y=-34}}} --> Equation 2
Therefore, the two numbers are -12 and -22.
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3. (Use the same steps)
{{{xy=-462}}}
{{{x=-462/y}}} --> Equation 1 ... Substitute {{{x=-462/y}}} into Equation 2
{{{x+y=-1}}} --> Equation 2
Therefore, the two numbers are -22 and 21.