Question 770599
using the digits0,1,2,3,4,5,6,7,8,9, how many 7 digit numbers can be formedif the first digit cannot be 0 or 9 and if the last digit is greater than or equal to 2 and less than or equal to 3? Repeated digits are allowed.  how does the calculation look.  Thanks
<pre>
There are 8 ways to choose the first digit as 1 thru 8
There are 10 ways each to choose the 5 middle digits as 0 thru 9
There are only 2 ways to choose the 7th digit as 2 or 3

Answer 8×10<sup>5</sup>×2 = 1600000.

Edwin</pre>