Question 770610
 y varies directly as x and inversely as z. 
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y = k*x/z
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Solve for "k" using "y=4/3 when x=3 and z=6.
4/3 = k*3/6
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8 = 3k
k = 8/3
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Equation:
y = (8/3)*x/z
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Find y when x=4 and z=3 
y = (8/3)*4/3
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y = 32/9 = 3 5/9
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Cheers,
Stan H.
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