<PRE><B>Question 770594</B>
The radioactive element americium-241 has a half-life of 432 years. Suppose we start with a 50-g mass of americium-241.
How much will be left after 375 years? Compute the answer to three significant digits.
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A(t) = Ao*(1/2)^(t/432)
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A(375) = 50*(1/2)^(375/432) = 50*0.5479
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A(375) = 27.4 grams
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Cheers,
Stan H.
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