Question 8498
You can always set your quadratic equation equal to zero.
1)
{{{2x^2 + 5 = 3}}} Subtract 3 from both sides.

{{{2x^2 + 5x - 3 = 0}}} This will factor nicely.

{{{(2x -1)(x + 3) = 0}}} Apply the zero product principle.

{{{2x - 1 = 0}}} or {{{x + 3 = 0}}}

If {{{2x - 1 = 0}}}, then, {{{2x = 1}}} and {{{x = 1/2}}}
If {{{x + 3 = 0}}}, then, {{{x = -3}}}

Try this approach on your second problem.