Question 769989
{{{x-y=7}}}
{{{x=y+7}}} --> Equation 1 ... Substitute {{{x=y+7}}} into Equation 2
{{{2/x-5/y=2}}}
{{{xy(2/x)-xy(5/y)=xy(2)}}}
{{{2y-5x=2xy}}} --> Equation 2
{{{2y-5(y+7)=2y(y+7)}}}
{{{2y-5y-35=2y^2+14y}}}
{{{-3y-35=2y^2+14y}}}
{{{0=2y^2+14y+3y+35}}}
{{{0=2y^2+17y+35}}}
{{{2y^2+17y+35=0}}}
{{{(2y+7)(y+5)=0}}}
{{{y=-7/2}}} or {{{y=-5}}}
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When {{{y=-7/2}}}, --> Substitute {{{y=-7/2}}} into {{{x=y+7}}}
{{{x=-7/2+7}}}
{{{x=7/2}}}
{{{x=3&1/2}}}
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When {{{y=-5}}}, --> Substitute {{{y=-5}}} into {{{x=y+7}}}
{{{x=-5+7}}}
{{{x=2}}}
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Therefore,
when {{{x=3&1/2}}}, {{{y=-7/2}}};
when {{{x=2}}}, {{{y=-5}}}.