Question 770458
{{{ log( 28 ) = log(( 3*7 )) }}}
{{{ log(( 3*7 )) = log( 3 ) + log( 7 ) }}}
{{{ log( 3 ) + log( 7 ) = .4771 + .845 }}}
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{{{ log( 144 / 49 ) = log( 12^2 / 7^2 ) }}}
{{{ log( 12^2 / 7^2 ) = log( ( 12/7 )^2 ) }}}
{{{ log( ( 12/7 )^2 ) = 2*log( 12/7 ) }}}
{{{ 2*log( 12/7 ) = 2*( log( 12 ) - log( 7 ) ) }}}
and
{{{ log(( 12 )) = log(( 3*2*2 )) }}}
{{{ log(( 3*2*2 )) = log(3) + 2*log(2) }}}
{{{ log(3) + 2*log(2) = .4771 + 2*.301 }}}
therefore:
{{{ log( 144/49 ) = 2*( log( 12 ) - log( 7 ) ) }}} 
{{{ log( 144/49 ) = 2*( .4771 + .602 - .845 ) }}}
( you can finish calculations )