Question 770438
Vertex is at {{{x=(-3+2)/2=-1/2}}}, so is the point (-1/2,25).  Feeding this into the standard form parabola equation, {{{y=a(x+1/2)^2+25}}}   .


Use either or both x-intercept points to find the value for a. 
{{{0=a(-3+1/2)^2+25}}}, what is a?
OR
{{{0=a(2+1/2)^2+25}}}, what is a?