Question 66240
please help to simplify 
3i - 5 
DIVIDED BY 
-i^3 + 3i^2

i=sqrt(-1)
i^2=-1
i^3=(i^2)(i)=-sqrt(-1)
-i^3=sqrt(-1)=i
3i^2=3(-1)=-3

Now we have
(3i-5)/(i-3)  Multiply numerator and denominator by (i+3) to get rid of the radical in the denominator and we have:

((3i-5)(i+3))/((i-3)(i+3))  Multiplying these out we get:

(3i^2-5i+9i-15)/(i^2-3i+3i-9)
(-3+4i-15)/-1-9
(4i-18)/-10  reduce by dividing both numerator and denominator by -2
(9-2i)/5



Hope this helps-----ptaylor