Question 770315
If sin xcox+sin2x=1, what are the values of x?
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sin(x)cos(x) = sin(2x)/2
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sin^2(2x) + sin(2x)/2 - 1 = 0
Sub u for sin(2x)
{{{u^2 + u/2 - 1 = 0}}}
*[invoke solve_quadratic_equation 1,.5,-1]
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Ignore the >1 answer
u =~ 0.780776
sin(2x) = 0.780776
2x = 0.8959,2.2457 + 2n*pi, n = 0,1,2,3...
x = 0.4482,1.1228 + n*pi, n = 0,1,2,3...