Question 769691
Please help my figure this out. Find tan &#952; if sec &#952; =(sqrt 26)/5 and sin &#952; < 0
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sec &#952;=&#8730;26/5
cos &#952;=5/&#8730;26
sin &#952;<0
This means reference angle is in Quadrant IV where sin<0 and cos>0
sin &#952;=-&#8730;1-cos^2 &#952;)=-&#8730;(1-25/26)=-&#8730;1/26=-1/&#8730;26
tan &#952;=sin &#952;/cos &#952;=-1/5