Question 769922
1) x = log2(128)
   x = log2(2^7)
   x = 7 log2 2
   x = 7 (log2 2 = 1)
2) log2x = -4
     x = 2^-4
     x = 1/16
3) log5(4x - 3) = 2
    4x - 3 = 5^2
    4x - 3 = 25
    4x = 25 + 3
    4x = 28
     x = 7
Hope this helps.
:-)