Question 769821
{{{9x^2+27x-4=0}}}

/9
{{{x^2+3x-(4/9)=0}}}


Third term = (1/2 the co-efficient of second term)^2

=(1/2 *3)^2
=9/4

{{{x^2+3x+(9/4) -9/4-4/9=0}}}

{{{(x+(3/2))^2 = 9/4 + 4/9}}}

{{{(x+(3/2))^2=(97/36)}}}

take square root

x+(3/2) = +/-sqrt(97)/6

x= -(3/2)+sqrt(97)/6 OR -(3/2)-sqrt(97)/6