<PRE><B>Question 66173</B>
What is the period and graph of y=2 cot(x+ pie over 2)?
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Form: y=acot(bx+c)+d
a=2, b=1, c=pi/2, 
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Period = pi/b=pi=180 degrees
Phase Shift = -c/b= -pi/2=-45 degrees
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Cannot graph functions like this on this site.
{{{graph(600,400,-360,360,-3,3,2cot(x+90))}}}
Vertical asymptotes occur at x=-pi/2=-45 degrees
and +pi/2=45 degrees.
Remember, cot is a decreasing function.

Cheers,
Stan H.</PRE>