Question 769654
1 jar contains 5/6 alcohol and another 8/9 alcohol . how many liters taken from each jar are required to fill a third jar with capacity of 24 liter so that the mixture will be seven eighths.
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alc + alc = alc
(5/6)x + (8/9)(24-x) = (7/8)24
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(5/6)x + (8/9)(24-x) = 21
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Multiply thru by 18 to get:
15x + 16*24 - 16x = 18*21
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-x = -6
x = 6 liters (amt to take from the (5/6) jar
24-x = 18 liters (amt to take from the (8/9) jar
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Cheers,
Stan H.