Question 769504
Suppose we assume the width to be {{{x}}}. The length is then {{{x+5}}}. 
The perimeter of a rectangle is 2(l+w), where l is the length and w is the width.
In this problem, the perimeter is 34, which means that {{{2(x+x+5)=34}}}. Dividing  both sides by 2 and simplifying, we get 2x+5=17. Subtracting 5 from both sides, we then find that 2x=12 and x=6.

The width is 6 and the length is 11.