Question 769467
1/2 (log7 x + log7 8) = log7 16

{{{log(7,sqrt(8x))-log(7,16)=0}}}


{{{log(7,sqrt(8x)/16)=0}}}


raising 7 to both sides yields:

{{{7^log(7,sqrt(8x)/16)=7^0}}}

i.e.

{{{sqrt(8x)/16=1}}}


so that 
{{{x=32}}}


:)