Question 769313
Last week Al bought some golf balls for $20. The next day they were on sale for $0.50 per ball less, and he bought $22.50 worth of balls. If he purchased 5 more balls on the second day than on the first day, how many did he buy each day and at what price per ball?
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Let original purchase be "x" balls at $20
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Next day value of the ball he bought was [(2000/x)-50)(x+5) = 2250
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Solve for "x":
(2000-50x)(x+5) = 2250x
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2000x + 10000 - 50x^2 - 250x = 2250x
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50x^2 +500x - 10000 = 0
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x^2 + 10x - 200 = 0
(x+20)(x-10) = 0
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Positive solution:
x = 10 (# purchased on 1st day)
x+5 = 15 (# purchased on 2nd day)
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Cheers,
Stan H.
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