Question 769265
Find solutions between [0,2PI)" 
4sin^2(theta)+7sin(theta)=2
4sin^2x+7sinx-2=0
use quadratic formula to solve for sinx
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=4, b=7, c=-2
ans:
sinx=-2 (reject, -1 < sinx < 1)
or
sinx=0.25