Question 769266
sin(2theta)=sqrt(2)cos(theta)
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{{{sin(2t) = sqrt(2)*cos(t)}}}
Use the double angle identity for sin(2t)
{{{2sin(t)*cos(t) = sqrt(2)*cos(t)}}}
{{{2sin(t)*cos(t) - sqrt(2)*cos(t) = 0}}}
{{{cos(t)*(2sin(t) - sqrt(2)) = 0}}}
cos(t) = 0
t = pi/2, 3pi/2
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{{{(2sin(t) - sqrt(2)) = 0}}}
{{{sin(t) = sqrt(2)/2}}}
t = pi/4, 3pi/4