Question 769266
find solutions between [0, 2PI)" 
sin(2theta)=sqrt(2)cos(theta)
sin2x=&#8730;2 cosx
2sinxcosx=&#8730;2cosx
divide both sides by cos x
2sinx=&#8730;2
sinx=&#8730;2/2
x=&#960;/4, 3&#960;/4 (in Q1 and Q2 where sin>0)