Question 769251
f(x)=
how i find the points (x,y) in order to graph this parabola?
This is an equation of a parabola that opens upwards.(lead coefficient>0)
Its standard form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex. A is a coefficient that affects the slope or narrowness of the curve.
With given equation, you have coordinates of the vertex (-1,-3)
Next, find the x-intercepts.
set y=0
1/2(x+1)^2-3=0
1/2(x+1)^2=3
(x+1)^2=6
(x+1)=±√6
x=-1±√6=-1±2.45
x=-3.45 and 1.45
You can now draw graph of given parabola with coordinates of the vertex, the x-intercepts, and knowing that the parabola opens upward.