Question 769065
Trying to make this as simple as possible, starting with m grams, rate of growth is r in its decimal fraction form, in the first hour, the mass becomes:
{{{m*(1+r)}}}
In 2 hours,---------{{{m*(1+r)*(1+r)}}}
In 3 hours, --------{{{m*(1+r)(1+r)(1+r)}}}
..
In x hours, --------{{{highlight(m*(1+r)^x)}}}


Use that pattern.  Your example uses m=100 and r=0.04 and x=10.  
Mass after 10 hours will be {{{highlight(100*(1.04)^10)}}} grams.

{{{highlight(148)}}} grams.



You could use log table if desired and then find antilog of the result.
{{{log(10,100*1.04^10)=log(10,100)+log(10,1.04^10)=2+10*log(10,1.04)}}}
{{{2+10*0.01770}}}
{{{2.17}}}
Most people these days use scientific calculators, so you're looking for {{{highlight(10^2.17=148)}}}.