Question 769015
Find two values of &#952;, 0 &#8804; &#952; < 2&#960;, that satisfy the given trigonometric equation.
If csc &#952; = &#8722;2, sin(theta) = -1/2
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Reference angle is pi/6
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Since the sin is negative theta is in QIII or QIV.
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Theta = p + pi/6 = (7/6)pi
OR
Theta = (2pi)-(pi/6) = (11/6)pi
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Cheers,
Stan H.