Question 768857
If sin qita = 1/3 , the find the value of 2 cot^2 qita + 2
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use x for qita
sin x=1/3
cos x=&#8730;(1-sin^2x)=&#8730;(1-1/9)=&#8730;(8/9)=&#8730;8/3
cot x=cos x/sin x=1/&#8730;8
cot^2 x=1/8
2 cot^2 x+2=x=1/4+2=9/4