Question 768861
function f(x)= 3x^3+7x^2-7x-3

It has one evident zero:  x = 1  (because sum of the coefficients is 0)

f(x) / (x-1) =  3x^2+10x+3

Then f(x) = (x-1)(3x^2+10x+3)

zeros of:  3x^2+10x+3  are:

-1/3 and -3  

Answer :  zeros of f(x) are:  1,-1/3 and -3

You can ask me more at: mthman@gmail.com

Thanks