<PRE><B>Question 768470</B>
how do i find all the real zeros of 2x^3+6x^2+5x+3? i found all the possible real zeros, but when i tried to solve for the real ones, i couldnt find any. the PRZ=1, -1, 3, -3, .5, -.5, 3/2, -3/2

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Real Number solution:::
I graphed the cubic and found a Real Number solution at x = -2.1654
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{{{graph(400,400,-10,10,-10,10,2x^3+6x^2+5x+3)}}}
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Cheers,
Stan H.
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