Question 768365
Identify the vertex, focus, and directrix of the graph
y=1/20(x-3)^2-3
(y+3)=(x-3)^2/20
(x-3)^2=20(y+3)
This is an equation of a parabola that opens upward.
Its basic form: (x-h)^2=4p(y-k), (h.k)=(x,y) coordinates of the vertex
For given parabola:
vertex: (3,-3)
axis of symmetry: x=3
4p=20
p=5
focus: (3,2) (p-units above vertex on the axis of symmetry)
directrix: y=-8 (p-units below vertex on the axis of symmetry)
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