Question 768392
Starting at middle E with a frequency of 328 cps, find the fequency of the note five half-steps above middle E.
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That's the note A.
A C# E is a major triad, so A:E = 4:6 --> A below E @ 328 is 328*4/6
The E an octave up is 2x that, = 328*4/3 Hz
=~ 437.33 Hz
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Another approach:
Each half-note = {{{root(12,2)}}}
A = {{{328*root(12,2^5)}}}
A =~ 437.83 Hz