Question 768030
Solve the equation sqr3 sinx = 1/2 sec x for 0 deg < x < 360 deg.
&#8730;3sinx=(1/2)secx=(1/2)(1/cosx)=1/2cosx
1/2sinxcosx=&#8730;3
1/sin2x=&#8730;3
sin2x=1/&#8730;3=&#8730;3/3
2x&#8776;35.26º, 144.73º
x&#8776;17.63º, 72.37º