Question 768115
Find two values of &#952;, 0 &#8804; &#952; < 2&#960;, that satisfy the given trigonometric equation.
sec &#952; = &#8722;2
cos&#952;=1/sec&#952;=-1/2
&#952;=2&#960;/3 and 4&#960;/3 (In Q2 and Q3 where cos and sec are<0)