Question 768308
Find two values of &#952;, 0 &#8804; &#952; < 2&#960;, that satisfy the given trigonometric equation.
csc &#952; = &#8722; 2&#8730;3/3
sin&#952;=1/csc&#952;=-3/2&#8730;3=-3&#8730;3/6=-&#8730;3/2
&#952;=4&#960;/3 and 5&#960;/3 (in Q3 and Q4 where sin and csc are<0)