Question 768302
write the expression as a single logarithm 
log(x^2+2x-3)/(x^2-4)-log(x^2+7x+6)/(x+2) 
log((x^2+2x-3)/(x^2-4)/(x^2+7x+6)/(x+2))
log(((x+3)(x-1)/(x+2)(x-2))/((x+6)(x+1)/(x+2)))
log(((x+3)(x-1)/(x+2)(x-2))*((x+2)/(x+6)(x+1)))
(x+2) cancels out
{{{log(((x+3)(x-1)/(x-2)*(x+6)(x+1)))}}}