Question 768291
<font face="Times New Roman" size="+2">


The way I learned the process, you don't swap the variables until the very last step.  But, giving it due consideration, it really shouldn't make any difference.  And, at least in the case of this problem, it doesn't.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  f(x)\ =\ 3\ -\ 2x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y\ =\ 3\ -\ 2x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  2x\ +\ y\ =\ 3]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  2x\ =\ 3\ -\ y]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x\ =\ \frac{3\ -\ y}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y\ =\ \frac{3\ -\ x}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  f^{-1}(x)\ =\ \frac{3\ -\ x}{2}]


See?


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>