Question 66071
ALL ARE OF SAME TYPE . I SHALL SHOW YOU ONE AND YOU TRY OTHERS.IF IN DIFFICULTY PLEASE COME BACK.
4) Solve the quadratic equation using the quadratic formula: 8x² - 10x - 2 = 0
FOR STANDARD QUADRATIC EQN. 
AX^2+BX+C=,THE ROOTS ARE
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
HERE A=8...B=-10....C=-2...SO PUTTING IN THE FORMULA ,WE GET
{{{x = (-(-10) +- sqrt( (-10)^2-4*8*(-2) ))/(2*8) }}} 
{{{x = (10 +- sqrt( 100+64 ))/(16) }}} 
{{{x = (10 +- sqrt( 164 ))/(16) }}} 

5) Solve the quadratic equation using the quadratic formula: 2x² - 5 = 4
6. Solve using the quadratic formula:
x² – 3x – 3 = -5
please if you can helpm me. thank you: