Question 768188
{{{F=8.69*ln(h) + 20}}}



Want h when F is known.
{{{F-20=8.69*ln(h)}}}
{{{ln(h)=(F-20)/8.69}}}


{{{highlight(h=e^((F-20)/8.69))}}}
Now assign 75 to F.  Compute h.


In case the code tagging and highlighting interfere, that formula is
h=e^((F-20)/8.69)