Question 66086
{{{ A = ((b[1]+b[2])h)/2 }}}
{{{ A = 224 }}}
{{{ h = 16 }}}
{{{ b[1] = 20 }}}
{{{ 224 = ((20+b[2])16)/2 }}}
multiply both sides by 2/16 to cancel the fraction
{{{ 224(2)/16 = (20+b[2]) }}}
Multiply and reduce the quantity on the left
{{{ 28 = 20 + b[2] }}}
subtract 20 from both sides
{{{ 8 = b[2] }}}