Question 768099
-5a², when a = -2
= -5(-2)² {substituted -2 in for a}
= -5(4) {evaluated exponent}
= -20 {multiplied}


√(b² - 4ac), when a = -1, b = 3, and c = -2
√[3² - 4(-1)(-2)] {substituted}
= √[9 - 8] {evaluated exponent and multiplied}
= √1 {subtracted}
= 1 {evaluated the square root of 1}
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