Question 66082
3=7x-4x^2
You lost your x^2
{{{4x^2-7x+3=7x-7x-4x^2+4x^2}}}
{{{4x^2-7x+3=0}}}
a=4, b=-7, and c=3
It looks like you want to use the quadratic formula, but this could have been solved through factoring.  I'm going to follow your lead and use the quadratic formula.
The quadratic formula is: {{{highlight(x=(-b+-sqrt(b^2-4ac))/2a)}}}
{{{x=(-(-7)+-sqrt((-7)^2-4(4)(3)))/(2(4))}}}
{{{x=(7+-sqrt(49-48))/8}}}
{{{x=(7+-sqrt(1))/8}}}
{{{x=(7-1)/8}}} or {{{x=(7+1)/8}}}
{{{x=6/8}}} or {{{x=8/8}}}
{{{highlight(x=3/4)}}} or {{{highlight(x=1)}}}
Happy Calculating!!!!