Question 767923
(√4:(7x^2y))/(√3:(4x^5y^2))
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= 2/(7x^2y) / sqrt(3)/(4x^5y^2)
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Invert the denominator and multiply to get:
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= 2/(7x^2y) * (4x^5y^2)/sqrt(3)
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= (2/sqrt(3))[28x^7y^3]
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= (2/3)sqrt(3)(28x^7y^3)
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Cheers,
Stan H.
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