Question 66004
(m^-2+n^-2)/(mn+m^-2n^-2)
=[(1/m^2)+(1/n^2)]/[mn+(1/m^2n^2)]
=[(n^2+m^2)/m^2n^2]/[(m^3n^3+1)/m^2n^2]
=[(n^2+m^2)/(m^2n^2] * [m^2n^2/(m^3n^3+1)]
=(n^2+m^2)/(m^3n^3+1)