Question 66007
Factor:
{{{2x^4-54x}}} Factor the 2x as you did.
{{{2x(x^3-27)}}} Now you may recognise the parentheses as the difference of two cubes for which the factored form is: {{{A^3 - B^3 = (A-B)(A^2+AB+B^2)}}}
Apply this to your equation: A = x and B = 3
{{{2x(x^3-27) = 2x((x)^3 - (3)^3)}}} = {{{2x(x-3)((x)^2+(3)(x)+(3)^2) = 2x(x-3)(x^2+3x+9)}}}